博客
关于我
CodeForces - 10A_模拟
阅读量:136 次
发布时间:2019-02-28

本文共 2279 字,大约阅读时间需要 7 分钟。

Tom is interested in power consumption of his favourite laptop. His laptop has three modes. In normal mode laptop consumes P1 watt per minute. T1 minutes after Tom moved the mouse or touched the keyboard for the last time, a screensaver starts and power consumption changes to P2 watt per minute. Finally, after T2 minutes from the start of the screensaver, laptop switches to the “sleep” mode and consumes P3 watt per minute. If Tom moves the mouse or touches the keyboard when the laptop is in the second or in the third mode, it switches to the first (normal) mode. Tom’s work with the laptop can be divided into n time periods [l1, r1], [l2, r2], …, [ln, rn]. During each interval Tom continuously moves the mouse and presses buttons on the keyboard. Between the periods Tom stays away from the laptop. Find out the total amount of power consumed by the laptop during the period [l1, rn].

Input
The first line contains 6 integer numbers n, P1, P2, P3, T1, T2 (1 ≤ n ≤ 100, 0 ≤ P1, P2, P3 ≤ 100, 1 ≤ T1, T2 ≤ 60). The following n lines contain description of Tom’s work. Each i-th of these lines contains two space-separated integers li and ri (0 ≤ li < ri ≤ 1440, ri < li + 1 for i < n), which stand for the start and the end of the i-th period of work.
Output

Output the answer to the problem.

Examples

Input

1 3 2 1 5 100 10

Output

30

Input

2 8 4 2 5 1020 3050 100

Output

570

题目大意:一台电脑有三种工作状态,每个工作状态有不同的耗电功率,求耗电值。


这题挺考察分类细节的,一个地方错了就过不了。

inline int f(int x, int l, int r){       return x * (r - l);}int main(){       int n, p1, p2, p3, t1, t2;    cin >> n >> p1 >> p2 >> p3 >> t1 >> t2;    int ans = 0;    int last = -1;    while (n--)    {           int a, b;        cin >> a >> b;        ans += f(p1, a, b);        if (last != -1)            if (a - last <= t1)            {                   ans += f(p1, last, a);            }            else            {                   ans += f(p1, last, last + t1);                if (a - last - t1 <= t2)                {                       ans += f(p2, last + t1, a);                }                else                {                       ans += f(p2, last + t1, last + t1 + t2);                    ans += f(p3, last + t1 + t2, a);                }            }        last = b;    }    cout << ans << endl;    return 0;}

转载地址:http://jeod.baihongyu.com/

你可能感兴趣的文章
mysql加强(4)~多表查询:笛卡尔积、消除笛卡尔积操作(等值、非等值连接),内连接(隐式连接、显示连接)、外连接、自连接
查看>>
mysql加强(5)~DML 增删改操作和 DQL 查询操作
查看>>
mysql加强(6)~子查询简单介绍、子查询分类
查看>>
MySQL单实例或多实例启动脚本
查看>>
MySQL压缩包方式安装,傻瓜式教学
查看>>
MySQL原理、设计与应用全面解析
查看>>
MySQL原理简介—1.SQL的执行流程
查看>>
mysql参考触发条件_MySQL 5.0-触发器(参考)_mysql
查看>>
MySQL及navicat for mysql中文乱码
查看>>
MySqL双机热备份(二)--MysqL主-主复制实现
查看>>
mysql启动以后会自动关闭_驾照虽然是C1,一直是开自动挡的车,会不会以后就不会开手动了?...
查看>>
mysql启动和关闭外键约束的方法(FOREIGN_KEY_CHECKS)
查看>>
Mysql启动失败解决过程
查看>>
MySQL启动失败:Can't start server: Bind on TCP/IP port
查看>>
mysql启动报错
查看>>
mysql启动报错The server quit without updating PID file几种解决办法
查看>>
mysql和oorcale日期区间查询【含左右区间问题】
查看>>
MySQL和SQL入门
查看>>
mysql在centos下用命令批量导入报错_Variable ‘character_set_client‘ can‘t be set to the value of ‘---linux工作笔记042
查看>>
Mysql在Linux运行时新增配置文件提示:World-wrirable config file ‘/etc/mysql/conf.d/my.cnf‘ is ignored 权限过高导致
查看>>